z^(2/3)-2z^(1/3)=15

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Solution for z^(2/3)-2z^(1/3)=15 equation: 


z in (-oo:+oo)

z^(2/3)-(2*z^(1/3)) = 15 // - 15

z^(2/3)-(2*z^(1/3))-15 = 0

z^(2/3)-2*z^(1/3)-15 = 0

t_1 = z^(1/3)

1*t_1^2-2*t_1^1-15 = 0

t_1^2-2*t_1-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

t_1 = (64^(1/2)+2)/(1*2) or t_1 = (2-64^(1/2))/(1*2)

t_1 = 5 or t_1 = -3

t_1 = -3

z^(1/3)+3 = 0

1*z^(1/3) = -3 // : 1

z^(1/3) = -3

( -3 < 0 i 1/3 in (0:1) ) => z należy do O

t_1 = 5

z^(1/3)-5 = 0

1*z^(1/3) = 5 // : 1

z^(1/3) = 5

z^(1/3) = 5 // ^ 3

z = 125

z = 125

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